If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+25x-524=0
a = 2; b = 25; c = -524;
Δ = b2-4ac
Δ = 252-4·2·(-524)
Δ = 4817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{4817}}{2*2}=\frac{-25-\sqrt{4817}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{4817}}{2*2}=\frac{-25+\sqrt{4817}}{4} $
| 4x*2-25x=0 | | -5(4c+7)=25 | | 3/4x-7/3x=19 | | -6=2x-35 | | )4x+8=7x+3-3x | | 17/4+4.2y-9/4=2.2y+6-2y-4 | | 5+86=78x+82-40x | | 50x-45=49x | | 2/5x+2/15=13/15 | | 2/3x=-21 | | 4x-5+3x+-4=180 | | 10^2x=10000 | | (-14)+x=28 | | 1.5u-9.59u-1.88=3.56 | | 10x=7x-12 | | 2^2x+128=3*2^x+3 | | 20=100k(100-100) | | 2/3x+2/3+1/5=2/3x | | 18x+2=6(3x+25) | | 3(2x-2)+8=34 | | 2(3w+7)/5=-5 | | -2(x6)=-36 | | 8(3s+9)=288 | | 3(2l+5)=20 | | 4x-2(x-5x)=2(x-5) | | 11+x=41 | | 2(x-6)-12=-3(x | | k2-k=42 | | 4(a-5)=20 | | 2(1/5+1/4x)-2x=x+1 | | 9+4(1+8c)=-35 | | 3=x^2-12 |